Question

how many real solutions do you get when you solve (x+6)2=0?

Answer 1

Question

how many real solutions do you get when you solve (x+6)2=0?

Solution

the factors of - 6 which sum to - 1 are - 3 and + 2

(x−3)(x+2)=0

equate each factor to zero and solve for

x

x+2=0⇒x=−2

x−3=0⇒x=3

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