Question

how many rectangles are possible of perimeter 40 cm find the area of each

Answer 1

unable to answer very tough question

Answer 2

Answer:

Only 1 rectangle needed for this:

If we consider 1 rectangle of length as 15 cm and breadth of 5 cm then the area would be 75 $cm^{2}$.

Proof:

Given, Perimeter as 40 cm and (15 cm + 5 cm)*2 = 40 cm.

And, Area = P L/2 - $L^{2}$

                  P = 40 cm

                  L = 15 cm

                  = 75 $cm^{2}$.