how many rectangles of a perimetre of 10 can be drawn
Answers
Answered by
1
perimeter = 2(l+b)
so
2(l+b)=10
(l+b)=5
Since length and width are positive integers in centimeters. Therefore, possible dimensions are
(2, 3). (1,4). (3,2) (4,1)
so
2(l+b)=10
(l+b)=5
Since length and width are positive integers in centimeters. Therefore, possible dimensions are
(2, 3). (1,4). (3,2) (4,1)
Answered by
0
Solution:-
Actually there can be infinite number of rectangles. Lemme explain,
perimeter = 2(L +B) = 10
⇒L +B = 5
now, we can take any positive number, can be fraction also.
It should be noted that L or B cannot be Zero, because if it is zero, then rectangle could not be formed.
If it is asked, the length and breadth can only be a natural number, then possible dimensions
are (length,breadth) as (2,3), (1,4), (3,2), (4,1)
then only 4 rectangles are possible.
Otherwise, infinite number of rectangles are possible.
==============
@GauravSaxena01
Actually there can be infinite number of rectangles. Lemme explain,
perimeter = 2(L +B) = 10
⇒L +B = 5
now, we can take any positive number, can be fraction also.
It should be noted that L or B cannot be Zero, because if it is zero, then rectangle could not be formed.
If it is asked, the length and breadth can only be a natural number, then possible dimensions
are (length,breadth) as (2,3), (1,4), (3,2), (4,1)
then only 4 rectangles are possible.
Otherwise, infinite number of rectangles are possible.
==============
@GauravSaxena01
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