Question

How many rectangles of perimeter 36 cm can be made if the sides in cm of the rectangle are odd numbers.

Answer 1

Answer: 5

Step-by-step explanation:

Given perimeter, P = 36 cm

Let length is l and breadth is b then perimeter of rectangle is

$P=2(l+b) \\\\\Rightarrow 36= 2(l+b)\\\\\Rightarrow 18=(l+b)$

So possible odd dimensions of the rectangle can be

1) 1 and 17

2) 3 and  15

3) 5 and 13

4) 7 and 11

5) 9 and 9  (All squares are rectangles)

Hence, there are five possible rectangle with perimeter 36 cm and dimension is odd number.

Answer 2

Answer:

its 5

Step-by-step explanation:

THE ANSWER IS 5 SEE ABOVE ANSWER FOR STEPS