how many rectangular slabs of 10 centimetre multiple 8 centimetre are required to cover the floor of the Hall Of 12 multiplied 10 metre
Answers
Answer:
Step-by-step explanation:
Dimension of rectangular slabs is = 10 * 8 sq. cm;
Area of a Slab is = 80 sq. cm;
Dimension of Hall = 12 * 10 Sq. m;
Area of Hall = 120 sq. m
we know that 1 meter = 100 cm;
So 120 Sq. m = 1200000 sq. cm;
No. of rectangular slabs = area of hall / area of one slab;
No. of rectangular slabs = 1200000/80 = 15000
Answer:
15000 rectangular slabs
Step-by-step explanation:
Area of hall = 12 m x 10 m = 120 square meter
Area of one rectangular slab = 10 cm x 8 cm = 80 square centimeter
In order to proceed further, the units of area of hall and rectangular slab should be same. we can convert either of them into other. Here, lets convert sq. meter into sq. cm.
1 m = 100 cm
1 m x 1 m ( 1 sq. m) = 100 cm x 100 cm = 10000 sq cm
Hence, 120 sq. m = 120 x 10000 sq. cm= 1200000 sq. cm
Now, as we can see area of one rectangular slab is 80 sq. cm. Hence, we can conclude that one rectangular slab will cover 80 sq. cm area of the hall.
Like wise 2 rectangular slab will cover 160 sq. cm
100 rectangular slab will cover 8000 sq. cm
we need to find how many rectangular slabs will cover entire 1200000 sq. cm
80 sq. cm is covered by 1 rectangular slab
Hence, 1200000 sq. cm will be covered by (1/80) x 1200000 rectangular slabs = 15000 rectangular slabs