Question

how many rectangular tiles 10 cm by 7 cm will be required to cover a floor 14 m by 25/2 m and what will the cost at rupay 5 per hundred tiles?​

Answer 1

Area of rectangle = length × breadth

Rectangular tiles 10 cm by 7 cm required to cover a floor 14 m by 25/2 m.

Here..

• Length of tile = 10 cm

• Breadth of tile = 7 cm

• Length of floor = 14 m

• Breadth of floor = 12.5 m (25/2)

Length and breadth of tiles are given in cm and length and breadth of floor is given in m.

Now, convert cm into m.

To convert cm into m divide by 100.

So,

• Length of tile = 0.1 m

• Breadth of tile = 0.07 m

According to question,

Area of tile = length × breadth

→ 0.1 × 0.07

→ 0.007 m²

Similarly,

Area of floor = length × breadth

→ 14 × 12.5

→ 175 m²

So,

Number of tiles required = Area of floor/Area of tiles

Substitute the known values above

→ 175/0.007

→ 25000

∴ 25000 tiles are required.

Cost per hundred tiles = Rs. 5

→ (25000 × 5)/100

→ 250 × 5

→ Rs. 1250

•°• Rs. 1250 is required.

Answer 2

Answer:

Step-by-step explanation:

Given :-

Dimension of times

Length of tiles = 10 cm

Breadth of tiles = 7 cm

Dimension of floor

Length of floor = 14 m

Breadth of floor = $\sf 12\frac{1}{2}$ m

To Find :-

Number of tiles needed

Cost of tiles

Formula to be used :-

Area of rectangle = Length × Breadth

Solution :-

Area of tiles = 10 cm × 7cm

Area of tiles = 70 cm²

Area of floor = 14m × 25/2 m

Area of floor = 175 m²

Converting m² into cm² = 175 × 10000 cm ²

= 1750000 cm²

Number of tiles needed = 1750000/70

Number of tiles needed = 25000

Cost of tiles = 5/100 × 25000

Cost of tiles = Rs 1250

Hence, The Number of tiles needed are 25000 and Cost of tiles Rs 1250.