Question

How many rectangular tiles 10cm by 7cm will be required to cover a floor 14m by 25/2m and what will be the cost at(5 rupees) per hundred tiles

Answer 1

In case of floor

Lenght=14m=1400 cm

breadth = 25/2m=1250cm

In case of tile

length = 10cm

breadth = 7cm

no.of tiles required = area of floor/area of tile

=1400×1250/10×7

=25000

so 25000 tiles are required

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Answer 2

Heya !!!

Length of tiles = 10 cm

Breadth of tiles = 7 cm

Area of tiles = L × B

=> 10 × 7

=> 70 cm

Length of floor = 14 m = 1400 cm

Breadth of floor = 25/2 m = 25/2 × 100

=> 25 × 50

=> 1250 cm

Area of floor = L × B

=>1400 × 1250

=> 1750000 cm²

Number of tiles required = Area of floor/Area of each tiles

=> 1750000/70

=> 25000

★ 100 tiles cost = Rs 5

1 tile = 5/100

1 tile cost = 0.05

Therefore,

Cost of 25000 tiles = 25000 × 0.05

=> Rs 1250.

HOPE IT WILL HELP YOU........ :-)