How many rectangular tiles 10cm by 8cm will be required to cover a floor 20 m long and 16 metre broad and what will be the cost at rupees 1150 tiles?
Answers
length of rectangular tile = 10 cm
breath of rectangular tile = 8 cm
Area of rectangular tile = length × breath
10 × 8
80 cm²
length of floor = 20 m × 100 = 2000 cm
breath of floor = 16 m × 100 = 1600 cm
area = length × breath
( 2000 × 1600 )
3200000 cm²
3200000 ÷ 100
32000
cost of a tile in area 1 m² = 1150
cost of tiles in area 32000 m² = 1150 × 32000
36800000 rupees
Answer:
17,500/-
Step-by-step explanation:
Length of tile = 10 cm
width of tile = 7 cm
Area of tile =70 sq cm
length of floor=14m=1400cm
width of the floor = 12.5cm = 1250cm
Area of floor = 1400×1250 sq cm
no.of tile required=(1400×1250)÷70
=25,000
Given, cost of 100 tile = 70/-
cost of 25000 tiles = (25000×70)÷100
17,500
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