Question

How many rectangular tiles 32 cm × 18 cm will be required to pave the floor of a hall 63 m × 4.8 m?

Answer 1

area of rectangular tiles= 0.32×0.18=0.0576
area of floor = 63×4.8=302.4
no. of tiles = 302.4/0.0576=5,250

Answer 2

Answer:

5250 tiles

Step-by-step explanation:

If we need to solve this , we need the area of the ground to be covered first.

Area of ground = l*b

= 63*4.8 = 302.4 m^2

= 302.4*m*m

=302.4*100*100 cm^2

=3024000 cm^2

Now ket us find the area of one rectangular tile

Area of tile = l*b

= 32*18 = 576 cm^2

Now number of tiles is nothing but area of ground by the area of each tile.

So we have n say number of tiles.

n = area of ground / area of tile

= 3024000/576

= 5250 tiles.

Hence the number of tiles required are 5250.

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