Question

How many rectangular tiles 32 cm ×18cm will be required to pave the floor of a hall 63 m ×4.8m?

Answer 1

Step-by-step explanation:

convert in same unit

then area of path = 6300×480 cm

area of tile =32×18cm

number of tile = area of hall ÷ area of tile

$\frac{6300 \times 480}{32 \times 18}$

no of tiles = 5250

Answer 2

$\tt ฏGIVEN:−$

$\tt length \: of \: floor = 4m =400cm$

$\tt breadth\: of \: floor= 3m = 300cm$

$\tt length\: of \: single \: tile= 8cm$

$\tt breadth\: of \: single \: tile= 6cm$

$\tt ฏFIND:-$

$\tt no. \: of \: tiles \: reqire = ?$

$\tt ฏSOLUTION:-$

$\tt area \: of \: floor = 400 \times 30 \\ \tt = 120000 {cm}^{2}$

$\tt area \: of \: each \: tile= 8 \times 6 = 4 {cm}^{2}$

$\tt now \: let \: no. \: of \: tiles = x$

$\tt = > area \: of \:hall= x\times area \: of \: each$

$\tt = > 120000 = x(48)$

$\tt = > x = \frac{ \cancel{ 120000}}{ \cancel{48}} = 2500$

$\boxed{ \tt so \: total \: no. \: of \: tile \: is \boxed{2500}}$