how many rectangular tiles 32cm * 18cm will be required to pave a factor of hall 8m by 4.5m
Answers
Answered by
1
Answer:
I think the answer is 625
Step-by-step explanation:
Hall dimensions = 8m = 800 cm
= 4.5m = 450 cm
Tile dimensions = 32 cm, 18 cm
No. of tiles required = Hall area/Tile area
= (800*450)/(32*18)
= 625 tiles
Hope it helps, if not, oh well.
Similar questions