Math, asked by veepra4400, 7 months ago

How many repeating digits are in 0 .ModifyingAbove 536 with bar? 1 2 3 4 Get the answers you need, now

Answers

Answered by pulakmath007
3

SOLUTION

TO CHOOSE THE CORRECT OPTION

 \sf{The  \: number \:  of \:  repeating  \: digits  \: in  \: 0. \overline{536}}

  • 1

  • 2

  • 3

  • 4

EVALUATION

Here the given number is

 \sf{0. \overline{536}}

Which can be rewritten as below

 \sf{0. \overline{536} = 0.536536536....}

So the digit which are repeating are 5 , 3 , 6

So the required number of repeating digits = 3

FINAL ANSWER

 \sf{The  \: number \:  of \:  repeating  \: digits  \: in  \: 0. \overline{536} \:  \: is \: 3}

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. The decimal expansion of 49/2³5³

contains six digits after the decimal point.

https://brainly.in/question/36368731

2. Without actually dividing find which of the following are terminating decimals.

i. 3/25 ii. 11/18 iii. 13/20 iv. 41/42

https://brainly.in/question/135746

3. without actually performing the long division state whether 13/3125 and 13/343 will have a terminating decimal expansion...

https://brainly.in/question/23797327

Answered by barani79530
1

Step-by-step explanation:

please mark as best answer and thank me

Attachments:
Similar questions