Question

How many resistances of 8 ohms should be joined in parallel to draw a current of 3 amperes from a
battery of 4 volts?
(a) 6
(b) 8
() 12
(d) 15

Answer 1

Answer:

6 resistors for explaination see attachment

Explanation:

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Answer 2

Answer:

(a) 6

Explanation:

Since V=IR

4 = 3 x R

Therefore R = 4/3 Ω

Since 1/Rp = 1/R1 + 1/R2 ...

Therefore 3/4 = 1/8 + 1/8 + 1/8 ... (individual resistance = 8Ω)

Therefore 3/4 = n(1/8)  (let no. of resistors be 'n')

Therefore 3/4 x 8 = n

Therefore n = 6

Hope it helps!