Question

how many resistor of 200ohms each are required in parallel combination, so as to carry 5A on a 200v line supply?​

Answer 1

Given :-

• Current = 5 Ampere
• Potential Difference = 200 Volts

To find :-

How many resistors of 200 Ω are required?

Solution :-

We are given the current and total resistance. For finding the total required resistance, we can apply Ohm's law.

   V = IR

⇒ R = V ÷ I

⇒ R = 200 ÷ 5

⇒ R = 40 Ω

Now, We need to find out how many resistances of 200 Ω are required to carry 40 Ω resistance

$\dashrightarrow \: \: \sf{x\bigg(\dfrac{1}{200}\bigg)=\dfrac{1}{40}}$

$\dashrightarrow \: \: \sf{\dfrac{x}{200} = \dfrac{1}{40}}$

$\dashrightarrow \: \: \sf{40x = 200}$

$\dashrightarrow \: \: \sf{x = \dfrac{200}{5}}$

$\therefore \boxed{\boxed{\bf{x=40}}}$