Question

How many resistors of 200ohm each are required in parallel
combination, so as to carry 5A on a 200V line supply?​

Answer 1

Answer:

The answer is 4 resistors.

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Answer 2

Given :

Resistance = 200Ω

To Find :

Number of resistors of 200Ω required to connect in parallel, so as to carry 5A on a 200V line supply$.$

Solution :

❒ We are given current flow and voltage of battery. From this data we can easily calculate equivalent resistance of the circuit.

• As per ohm's law current flow in conductor is directly proportional to the applied potential difference at constant temperature.

Mathematically, V = I × R

» V denotes pd

» I denotes current

» R denotes resistance

By substituting the given values;

➙ V = I × Rp

➙ 200 = 5 × Rp

➙ Rp = 200/5

➙ Rp = 40Ω

∴ Eq. resistance of circuit = 40Ω

Let n resistors each of 200Ω are connected in parallel.

Equivalent resistance of parallel connection is given by

➙ 1/Rp = 1/R₁ + 1/R₂ + ... + 1/Rₙ

➙ 1/Rp = 1/R + 1/R + ... + 1/R

➙ 1/Rp = n/R

➙ Rp = R/n

➙ 40 = 200/n

➙ n = 200/40

➙ n = 5

∴ Five resistors each of 200Ω should be connected in parallel.