How many resistors of 88 ohms are connected in parallel to carry 10 a current on a220 v line?
Answers
Answered by
13
No. of resistors=IR/V
=10*88/220
=880/220
=4
saniyaarora2003:
in series
ya ya
same
ok
just wait
no its 2.5 in series
in series 22+22+22+22 =88ohm. i prallel 1/22+1/22+1/22+1/22=5.5 ohm its coming 5.5 ohm . but u say if we connect 22 ohm s 4 resistor in parellell then total resistance is 88ohm
why so
hope u will reply till 2020
will be waiting
Answered by
9
The answer will be 4 resistance
If u want explanation aske in comments
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