How many revolutions does the engine make during this time?
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Answered by
0
Answer:
The angular acceleration is
=
15.71
r
a
d
s
−
2
and the number of revolutions is
=
419.9
Explanation:
The initial angular speed is
ω
0
=
1200
⋅
2
π
60
=
40
π
r
a
d
s
−
1
The final angular speed is
ω
1
=
3000
⋅
2
π
60
=
100
π
r
a
d
s
−
1
The time is
t
=
12
s
Apply the equation of motion
ω
1
=
ω
0
+
α
t
The angular acceleration is
α
=
ω
1
−
ω
0
12
=
100
π
−
40
π
12
=
15.71
r
a
d
s
−
2
Apply the equation
ω
2
1
=
ω
2
0
+
2
α
θ
The angle travelled is
θ
=
ω
2
1
−
ω
2
0
2
α
=
(
100
π
)
2
−
(
40
π
)
2
2
⋅
15.71
=
2638.6
r
a
d
=
419.9
revolutions
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