Biology, asked by dastiteersha, 4 months ago

How many RNA primers are required to synthesize 10 okazaki fragments during DNA replication​

Answers

Answered by lalitnit
0

Answer:

DNA synthesis always occurs in the 5'-->3' direction because chain growth results from the formation of a phosphodiester bond between the 3' oxygen of a growing strand and α phosphate of a dNTP.

To facilitate the growth of the lagging strand in the 5'-->3' direction, copying of its template strand must somehow occur in the opposite direction from the movement of the replication fork, i.e., in 3’ to 5’ direction; option C is correct. This is done by synthesizing a new primer every few hundred bases on the second parental strand. Each of these primers is elongated in the 5'-->3' direction and form discontinuous segments called Okazaki fragments which are later joined together by DNA ligase.

The semiconservative mechanism of DNA replication in which a DNA strand serves as a template for the synthesis of a new strand and produces two new DNA molecules, each with one new strand and one parental strand, is followed by both DNA strands.

Transcription is the process of RNA synthesis using DNA template strand which is carried out by RNA polymerase; any of two DNA strands can serve as the template.

Answered by sabrinamoore
0

Answer:

DNA polymerase then incorporates a dNMP onto the 3' end of the primer initiating leading strand synthesis. Only one primer is required for the initiation and propagation of leading strand synthesis. Lagging strand synthesis is much more complex and involves five steps

Explanation:

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