Question

How many roots of this quadratic equation and which are they? don't spam

Answer 1

let x/(x+1) = y

∴ 5[x/(x+1)]^2 - 4[x/(x+1)] - 1 = 0

= 5y^2 - 4y - 1 = 0

= 5y^2 -5y + y - 1 = 0

= 5y(y - 1) + (y - 1) = 0

= (5y + 1)(y - 1) = 0

  (5y + 1) = 0           and ; (y - 1) = 0

y = -1/5                    and ; y = 1

x/(x+1) = -1/5             and  ;  x/(x+1) = 1

5x = -x -1                  and ; x = x+1

x = -1/6              and      ; x = x+1   (not possible)