how many roots will the equator equation x square + 2x + 4 = 0 have?
Answers
Answered by
6
Hiii friend,
P(X) => X²+2X +4 = 0
Highest degree of X is 2 . So the given polynomial have two equal roots which are,
X²+2X+4 = 0
X²+2X+2X+4 = 0
X(X+2) +2(X+2) = 0
(X+2) (X+2) = 0
(X+2) = 0 OR (X+2) = 0
X = -2 or X = -2
Hence,
The given polynomial have two equal roots
HOPE IT WILL HELP YOU...... :-)
P(X) => X²+2X +4 = 0
Highest degree of X is 2 . So the given polynomial have two equal roots which are,
X²+2X+4 = 0
X²+2X+2X+4 = 0
X(X+2) +2(X+2) = 0
(X+2) (X+2) = 0
(X+2) = 0 OR (X+2) = 0
X = -2 or X = -2
Hence,
The given polynomial have two equal roots
HOPE IT WILL HELP YOU...... :-)
Answered by
2
Solution:-
given by the equetion:-

given by the equetion:-
Similar questions