How many runs a single player can score in One day match (50 overs/ 300 balls)
No 'no balls', no wides, no extras, no over throws...So how much runs he can score max???
Answers
Cricket is here:
We put the player on strike and in order to come to strike in the very first ball of next overs, he must go to non-strike end in the last ball of an over.
However his 50 overs can be taken like this:
- 1st over : 6 6 6 6 6 3 = 33
- 2nd over : 6 6 6 6 6 3 = 33
- 3rd over : 6 6 6 6 6 3 = 33
In this way, he will play till the last ball of 49th over.
So his total runs till 49th over be
= 49 × 33
= 1617
In the 50th over, he can score 6 6 6 6 6 6, a total of 36 runs.
Therefore the player's innings total be
= 1617 + 36 = 1653, which is the maximum runs he can score.
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Given data:
A player should score in a One-day match (50 overs/ 300 balls) with no 'no balls', no wides, no extras, no overthrows.
To find:
The maximum runs he could score as per the information given.
Solution:
To get the maximum runs under the given condition,
For the first 49 overs, the first five balls of each over should get hit as a six.
The last ball of each over should be a 3 run, in order to get the strike for the next over as in maximum (as there are no overthrows.)
So, for each over in the first 49 overs, we get
For first 5 balls of the over : 5 x 6 = 30
For the last ball of the over: 1 x 3 = 3
Total per over = 30+3 = 33 runs
So, for the first 59 overs, he scores 33 x 49 = 1617 runs
In the last over, as the strike stays with him throughout, he can hit 6 sixes out of the park and finish the match.
So, in the last over i.e., 50th over, he scores 6 x 6 = 36 runs
Total runs he score in the 50 overs = 1617 + 36 = 1653 runs.
Therefore, the maximum number of runs the player can score in a one-day match of 50 overs is 1653 runs (with no 'no balls', no wides, no overthrows, no extras).
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