How many sets of values are possible for two numbers a and b where lcm of a and b is 28?
Answers
Answered by
0
=23 .
it's your answer
Answered by
2
Given : two numbers a,b where lcm of a,b is 28
To find : sets of values a,b
Solution:
LCM of ( a, b ) is 28
28 = 1 * 2 * 2 * 7
a = 1 then b = 28
a = 2 then b = 28
a = 4 Then b = 7 , 14 , 28
a = 7 then b = 4 , 28
a = 14 then b = 4 , 28
a = 28 then b = 1 , 2 , 4 , 7 , 14 , 28
( 1 , 28 ) , ( 2, 28 ) , ( 4 , 7) , ( 4 , 14) , ( 4 , 28 ) , (7 , 28 ) , ( 14 , 28) , ( 28 , 28)
or
(28 , 1) , (28 , 2) ,(7 , 4) , (14 , 4) (28 , 4) , ( 28 , 7) , (28 , 14)
Learn More:
Can you find the numbers if lcm of two numbers is 75,, gcd is 25. justify
https://brainly.in/question/14601305
The LCM (24,n)= 20 and HCF(24,n) =4n find the value of "n ...
https://brainly.in/question/13034138
Similar questions