Math, asked by singhtanvir902, 1 year ago

How many sides a polygon have if each of its angles is 108

Answers

Answered by Panmri
2
The answer given here is only for a regular polygon. Each interior angle of the polygon is 108 degrees, so each exterior angle of the polygon is 180-108 = 72 degrees. So the number of sides is 360/72 = 5. Hence it is a regular pentagon.
Answered by Tejaa1
0
each interior angle of a regular polygon is
 \frac{(n - 2) \times 180}{n}  = 108
solving for n, we get n=5. it's a regular Pentagon.
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