how many sides a regular polygon has with its sum of interior angles eight times its sum of exterior angles?
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octagon i think is the answer
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Here is ur answer,
Sum of exterior angles=360°
Sum of interior angles= 360°*8= 2880°
Sum if interior Angles= (n-2)*180°
Here, (n-2)*180=2880°
Substitute the value of n
Here, n = sides
n-2= 2880/180
n-2= 16
n=18
There are 18 sides in the polygon
Hope u got it
Plz Mar k it as brainiest
Sum of exterior angles=360°
Sum of interior angles= 360°*8= 2880°
Sum if interior Angles= (n-2)*180°
Here, (n-2)*180=2880°
Substitute the value of n
Here, n = sides
n-2= 2880/180
n-2= 16
n=18
There are 18 sides in the polygon
Hope u got it
Plz Mar k it as brainiest
kirtikewat:
thanku
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