How many sides does a regular polygon have, wherein, whose interior angle is eight times its exterior angle
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Answer:
Interior angle of a regular polygon of 'n' sides =
n
(n−2)×180
∘
Exterior angle of a regular polygonof 'n' sides
Given,
n
(n−2)×180
∘
=8×
n
360
∘
⇒(n−2)=8×
180
∘
360
∘
=16
⇒n=18
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