Question

How many sides does a regular polygon have, wherein, whose interior angle is eight times its exterior angle ?

Answer 1

Let the no. of side be n.

• Each interior angle = [(n-2)·180]/n

• ""      exterior  ''  ''  = 360/n

A/Q  [(n-2)·180]/n = 8 (360/n )

   ⇒ (n-2)  = 8 x 360/180

  ⇒  n-2 = 16

So

n = 18

Answer 2

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