how many sides of a regular polygon have if each of its interior angle is
(i) 144
(ii) 160
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Measure of interior angle
= (n-2)180°/n
(i)
144° = (n-2)180°/n
144°n = 180°n - 360°
-36°n = -360°
n = 10
(ii)
160° = (n-2)180°/n
160°n = 180°n - 360°
-20°n = -180°
n = 9
= (n-2)180°/n
(i)
144° = (n-2)180°/n
144°n = 180°n - 360°
-36°n = -360°
n = 10
(ii)
160° = (n-2)180°/n
160°n = 180°n - 360°
-20°n = -180°
n = 9
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