How many sigma and pi bonds present in HC_
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Explanation:
ANSWER
Answer:-
H−C
π
≡
π
C−
H
∣
C
=
π
H
∣
C
−
H
∣
C
∣
H
−H
HC≡C−CH=CH−CH
3
No. of σ bonds = 10
No. of π bonds = 2+1 = 3 ( two from one triple bond and one from a double bond).
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