Chemistry, asked by h144sampathk, 5 months ago

How many significant figures are present in 0.00258× 10^7 ?

Answers

Answered by kritanuchatterjee280

0

Answer:

5 significant figures

Explanation:

0.00258 x 10⁷ = 25800.

Thus, the number obtained as result has 5 digits and hence, it contains 5 significant figures.

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