Chemistry, asked by Sagarmishrastc, 9 months ago

how many significant figures are present in the volume of a wooden block of mass 32.4 gram is the density of the wooden block is 16 gram per centimetre cube​

Answers

Answered by Anonymous
2

Answer:

Explanation:

Volume = Mass/Density

             = 32.4/16

Volume = 2.025

Rounding off = 2.0

Rounding off is necessary because least number of significant figure present in questions is 2.

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Answered by anjali13lm
0

Answer:

In the observed volume of the wooden block, the significant figures present are 2.

The volume of the wooden block is 2.0cm^{3}.

Explanation:

Given,

The mass of the wooden block, m = 32.4g

The wooden block's density, ρ = 16g/cm^{3}

The volume of the wooden block, V =?

The significant figures present in the volume of the wooden block =?

As we know,

  • Density is defined as the mass per unit volume
  • \rho =\frac{m}{V}
  • V =\frac{m}{\rho}

After putting the given values in the equation, we get:

  • V = \frac{32.4}{16} = 2.025 cm^{3}

Now, as given,

  • Number of significant figures in density ( 16g ) = 2
  • Number of significant figures in mass ( 32.4 ) = 3

Hence, the volume should have the number of significant figures less/equal to the least significant figures; i.e., density ( 2 ).

Therefore,

  • The significant figures present in the volume = 2

Hence, the volume of the wooden block, V = 2.0 cm^{3}.

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