Question

how many significant figures are present in the volume of a wooden block of mass 32.4 gram is the density of the wooden block is 16 gram per centimetre cube​

Answer 1

Answer:

Explanation:

Volume = Mass/Density

             = 32.4/16

Volume = 2.025

Rounding off = 2.0

Rounding off is necessary because least number of significant figure present in questions is 2.

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Answer 2

Answer:

In the observed volume of the wooden block, the significant figures present are $2$.

The volume of the wooden block is $2.0cm^{3}$.

Explanation:

Given,

The mass of the wooden block, m = $32.4g$

The wooden block's density, ρ = $16g/cm^{3}$

The volume of the wooden block, V =?

The significant figures present in the volume of the wooden block =?

As we know,

• Density is defined as the mass per unit volume
• $\rho =\frac{m}{V}$
• $V =\frac{m}{\rho}$

After putting the given values in the equation, we get:

• V = $\frac{32.4}{16}$ = $2.025 cm^{3}$

Now, as given,

• Number of significant figures in density ( $16g$ ) = $2$
• Number of significant figures in mass ( $32.4$ ) = $3$

Hence, the volume should have the number of significant figures less/equal to the least significant figures; i.e., density ( $2$ ).

Therefore,

• The significant figures present in the volume = 2

Hence, the volume of the wooden block, V = $2.0 cm^{3}$.