Question

How many silver atoms are present in a piece of jewellery weighing 10.78g? Ag=107.8
a.m.u.​

Answer 1

6.02×10 to the power 22

Explanation:

number of atoms in a compound =number of moles present in the compound ×avogadro number

number of moles =given mass÷atomic mass

which here is 10.78÷107.8= 0.1 moles

number of atoms thus equall to 0.1 × avogadro number

and hence the answer

hope you understand