how many silver atoms are present in a piece of jewelry weighing 10.78 gram of Ag = 107.8 a.m.u
Answers
Answered by
12
it's easy by other mole formula you can find it..
mole =6.022×10power 23
mole =6.022×10power 23
Answered by
12
no of moles=weight/molecular mass
=10.78/107.8×10^-10
=1 ×10^9
=10.78/107.8×10^-10
=1 ×10^9
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