How many silver coins 1.75 cm in diameter and of thinkness 2mm must be melted to form a cuboid of dimension 5.5cm×10cm×3.5cm?
nagarajgogre0125:
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Answers
Answered by
7
Solution:
Radius of coin = 0.875 cm,
height = 0.2 cm
Dimensions of cuboid = 5.5 cm x 10 cm x 3.5 cm
Volume of coin=
=π × 0.875 × 0.875 × 0.2
= 0.48125
Volume of cuboid = 5.5 x 10 x 3.5 = 192.5 cm3
Number of coins = 192.5 / 0.48125 = 400
❤️
Radius of coin = 0.875 cm,
height = 0.2 cm
Dimensions of cuboid = 5.5 cm x 10 cm x 3.5 cm
Volume of coin=
=π × 0.875 × 0.875 × 0.2
= 0.48125
Volume of cuboid = 5.5 x 10 x 3.5 = 192.5 cm3
Number of coins = 192.5 / 0.48125 = 400
❤️
Answered by
8
400 coins
step-by-step explanation:
Given,
for silver coins,
we know that it is cylinder,
diameter = 1.75 cm
.°. radius, r = 1.75/2 cm
and,
height, h = 2mm = 2/10 cm = 0.2 cm
.°. Volume, V =
=> V =
=> (0.6125π/4)
Now,
For Cuboid,
length, l = 10 cm
breadth, b = 5.5 cm
height, H = 3.5 cm
.°. Volume, V' = lbH
=> V' = 192.5
Now,
Let,
the number of coins be ' n '
now,
it is given that the coins are being melted to form this cuboid
therefore,
the vloume of all coins must be equal to the Volume of the Cuboid
=> nV = V'
=> n = V'/V
=> n = 4×192.5 / 0.6125π
=> n = 4× 314/3.14
=> n = 400
Hence,
400 coins are melted to form the cuboid.
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