How many silver coins, 1.75 cm. in diameter and thickness 2 mm., need to be melted to form a cuboid of dimensions 5.5 cm. ×10 cm. × 3.5 cm.?
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Hi ,
i ) Dimensions of the each silver coin
( cylinder ):
diameter ( d ) = 1.75 cm
radius ( r ) = d/2 = ( 1.75/2 ) cm
thickness = height ( h ) = 2mm =( 1/5 )cm
volume of each coin = V1
V1 = πr²h
= ( 22/7 ) × ( 1.75/2 )² × ( 1/5 )
V1 = 0.48125 cm³ ----( 1 )
ii ) Dimensions of the cuboid :
length ( l ) = 5.5 cm
breadth ( b ) = 10 cm
height ( H ) = 3.5 cm
Volume of the Cubiod = V2
V2 = lbh
= 5.5 cm × 10cm × 3.5 cm
= 175 cm³----( 2 )
according to the problem given ,
Let " n " silver coins melted to form
required cuboid .
n = V2/V1
= ( 2 )/( 1 )
= 175/( 0.48125 )
= 363.636
≈ 364
Therefore ,
364 required to make a cuboid.
I hope this helps you.
: )
i ) Dimensions of the each silver coin
( cylinder ):
diameter ( d ) = 1.75 cm
radius ( r ) = d/2 = ( 1.75/2 ) cm
thickness = height ( h ) = 2mm =( 1/5 )cm
volume of each coin = V1
V1 = πr²h
= ( 22/7 ) × ( 1.75/2 )² × ( 1/5 )
V1 = 0.48125 cm³ ----( 1 )
ii ) Dimensions of the cuboid :
length ( l ) = 5.5 cm
breadth ( b ) = 10 cm
height ( H ) = 3.5 cm
Volume of the Cubiod = V2
V2 = lbh
= 5.5 cm × 10cm × 3.5 cm
= 175 cm³----( 2 )
according to the problem given ,
Let " n " silver coins melted to form
required cuboid .
n = V2/V1
= ( 2 )/( 1 )
= 175/( 0.48125 )
= 363.636
≈ 364
Therefore ,
364 required to make a cuboid.
I hope this helps you.
: )
lol5317:
The answer is wrong
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