How many silver coins 1.75cm in diameter and of thickness 2mm, must be melted to form a cuboid of dimensions 5.5cm×10cm×3.5?
Answers
Answer:
Step-by-step explanation:
Let the number of coin be x
x× volume of 1 coin = volume of box
x×πr
2
h=l×b×h
x×
7
22
×
100×2
175
×
100×2
175
×
10
2
=
10
55
×10×
10
35
x=
22×25×175
55×35×100×100×2
=20×20
=400coins
We have,
Radius of coin = 1.75/2 = 00.875 cm
Thickness, i.e, height = 2/10 = 0.2 cm
The shape of the coin will be like the shape of cylinder
Volume of the coin = πr²h
Volume of the coin = 22/7 × 0.875 × 0.875 × 0.2
Now, Volume of the cuboid = 5.5 × 10 × 3.5
Therefore, Number of coins required to form a cuboid = Volume of the cuboid/Volume of the coin
Number of coins required to form a cuboid = 5.5 × 10 × 3.5/22/7 × 0.875 × 0.875 × 0.2
Number of coins required to form a cuboid = 400
Hence, There are 400 silver coins melted to form a cuboid.