how many silver coins,1.75cm in diameter and of thickness2mm must be melted to form a cuboid of dimension 5.5cm,10cm,3.5 cm?
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height = 2mm = 0.2 cm
diameter = 1.75 cm
radius = diameter / 2 = 1.75 /2 = 0.875 cm
dimensions of cuboid
length = 5.5 cm
breadth = 10 cm
height = 3.5 cm
volume of one silver coin
= pi * ( r ^2 )
= 3.141 (0.875 )(0.875) (0.2)
= 0.481 cm ^ 3
volume of cuboid
= l * b * h
= 5.5 ( 10 ) (3.5)
= 192.5 cm ^3
no .of coins required to form cuboid
= volume of cuboid / volume of one coin
= 192.5 /0.481
= 400.207
= 401 ( rounded to next nearest number)
diameter = 1.75 cm
radius = diameter / 2 = 1.75 /2 = 0.875 cm
dimensions of cuboid
length = 5.5 cm
breadth = 10 cm
height = 3.5 cm
volume of one silver coin
= pi * ( r ^2 )
= 3.141 (0.875 )(0.875) (0.2)
= 0.481 cm ^ 3
volume of cuboid
= l * b * h
= 5.5 ( 10 ) (3.5)
= 192.5 cm ^3
no .of coins required to form cuboid
= volume of cuboid / volume of one coin
= 192.5 /0.481
= 400.207
= 401 ( rounded to next nearest number)
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