How many silver coins,1.75cm.in diameter and thickness 2mm, need to melted to form a cubiod of dimensions 5.5 cm *10cm*
3.5cm
Answers
Answer:
Assume silver coin to be a cylinder
Dimensions of silver coin
Height= 2 mm = 0.2 cm
Diameter= 1.75 cm
Radius= Diameter/2 = 1.75/2 = 0.875 cm
Dimensions of cuboid
Length= 5.5 cm
Breadth= 10 cm
Height = 3.5 cm
Volume of one silver coin
= pi *(r^2)*h
= 3.141(0.875)(0.875)(0.2)
= 0.481 cm^3
Volume of cuboid
= l * b * h
= 5.5(10)(3.5)
= 192.5 cm^3
No. of coins required to form cuboid
= Volume of cuboid/Volume of one coin
= 192.5/0.481
= 400.207
= 401 (rounded to next nearest number)
The answer is 401
Hope it helps.
Answer:
401
Step-by-step explanation:
Assume silver coin to be a cylinder
Dimensions of silver coin
Height= 2 mm = 0.2 cm
Diameter= 1.75 cm
Radius= Diameter/2 = 1.75/2 = 0.875 cm
Dimensions of cuboid
Length= 5.5 cm
Breadth= 10 cm
Height = 3.5 cm
Volume of one silver coin
= pi *(r^2)*h
= 3.141(0.875)(0.875)(0.2)
= 0.481 cm^3
Volume of cuboid
= l * b * h
= 5.5(10)(3.5)
= 192.5 cm^3
No. of coins required to form cuboid
= Volume of cuboid/Volume of one coin
= 192.5/0.481
= 400.207
= 401 (rounded to next nearest number)
The answer is 401
Hope it helps.