How many silver coins 2cm in diameter and of thickness 2mm must be melted to form a showpiece in the form of a frustum of cone having height 9cm and radii of outer circular ends as 5cm and 3cm
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Step-by-step explanation:
if the cone were complete, it would have height 45/2, so the missing part has height 27/2.
So, if there are x coins,
(π*0.2*1^2)x = π/3 (5^2*45/2 - 3^2*27/2)
x = 735
Hope this answer would be marked as the brainliest
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