how many silver coins d=1.75 thickness =2m must be melting to foam cuboids dimensions=5.5×10×3.5
Answers
Answered by
4
no of coins required = volume of cuboid / volume of one coin
volume of cuboid = l×b×h
= 5.5× 10× 3.5
volume of coin =
pie 1.75/2× 1.75/2 × 2
no. of coins required= 5.5×10×3.5/ pie × 1.75/2×1.75/2×2
=192.5/4.81
= 40
so 40 coins are required
HOPE IT HELPS! !!!!
please mark as brainlist
volume of cuboid = l×b×h
= 5.5× 10× 3.5
volume of coin =
pie 1.75/2× 1.75/2 × 2
no. of coins required= 5.5×10×3.5/ pie × 1.75/2×1.75/2×2
=192.5/4.81
= 40
so 40 coins are required
HOPE IT HELPS! !!!!
please mark as brainlist
GeniusUjjwal:
mark as brainlist pls
Answered by
0
Hi friend,
Here is your answer,
◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕
__________________________________________________________
Let the number of coins be x .
Volume of x coins = Volume of the cuboid
x * π * r² * h = l * b * h
x * ²²/₇ * ¹⁷⁵/₁₀₀* ¹⁷⁵/₂₀₀ * 2 = 5.5×10×3.5
x = 40
40 silver coins must be melted to form a cuboid of 5.5×10×3.5 dimensions.
_________________________________________________________
◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕
HOPE THIS HELPS YOU !!
PLS MARK AS BRAINLIEST !!
Here is your answer,
◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕
__________________________________________________________
Let the number of coins be x .
Volume of x coins = Volume of the cuboid
x * π * r² * h = l * b * h
x * ²²/₇ * ¹⁷⁵/₁₀₀* ¹⁷⁵/₂₀₀ * 2 = 5.5×10×3.5
x = 40
40 silver coins must be melted to form a cuboid of 5.5×10×3.5 dimensions.
_________________________________________________________
◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕ ◕‿◕
HOPE THIS HELPS YOU !!
PLS MARK AS BRAINLIEST !!
Similar questions