How many silver coins of diameter 4cm and thickness 3.5mm have to be melted to
prepare a cuboid of 20cm x 11cm x 5cm dimensions.
Answers
Answer:
Assume silver coin to be a cylinder
Dimensions of silver coin
Height= 2 mm = 0.2 cm
Diameter= 1.75 cm
Radius= Diameter/2 = 1.75/2 = 0.875 cm
Dimensions of cuboid
Length= 5.5 cm
Breadth= 10 cm
Height = 3.5 cm
Volume of one silver coin
= pi *(r^2)*h
= 3.141(0.875)(0.875)(0.2)
= 0.481 cm^3
Volume of cuboid
= l * b * h
= 5.5(10)(3.5)
= 192.5 cm^3
No. of coins required to form cuboid
= Volume of cuboid/Volume of one coin
= 192.5/0.481
= 400.207
= 401 (rounded to next nearest number)
The answer is 401
Answer:
Step-by-step explanation:
Silver coin is in cylindrical shape.
Diameter=4cm
Radius=2cm
Thickkness(h)=3.5mm=0.35cm.
Volume of a coin=22÷7×2×2×3.5=4.4 cubic cm
Volume of a cuboid=l×b×h
Length=20cm
Breadth=11cm
Height = 5cm
Volume=20cm×11cm×5cm=
=1100 cubic cm
How many coins required =volume of cuboid÷volume of one coin
=1100÷4.4
=25
:25 coins are requiredto makea cuboid.