how many silver coins of diameter 5 cm and thickness 4 mm are to be melted to prepare a cuboid of 12 cm 11 cm 25 cm dimensions
Answers
Answer:
Step-by-step explanation:
The volume of the cuboid =(12×11×5) cm³
=(12×11×5) cm³
The thickness of each coin = (4/10) cm [1 cm = 10 mm]
= (2/5) cm
The radius of each coin = (5/2) cm
= (5/2) cm
The volume of each coin = πr²h
= (22/7)×(5/2)²×(2/5)
= (22×5×5×2) ÷ (7×2×2×5)
= (55/7) cm³
The number of coins have to be melted = (12×11×5)÷(55/7)
= (12×11×5×7)/55
= (12×7)
= 84
Answer:-
84 coins have to be melted to prepare a cuboid of 12 cm × 11 cm ×5 cm
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