Math, asked by Ananya1098, 1 year ago

How many silvercoins, 1.75 cm in diameter and of thickness 2 mm, must be melted to form a cuboids of dimensions5.5 cm × 10 cm × 3.5 cm?

Answers

Answered by anantaw
2

Answer:

Step-by-step explanation:

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Assume silver coin to be a cylinder

Dimensions of silver coin

Height= 2 mm = 0.2 cm

Diameter= 1.75 cm

Radius= Diameter/2 = 1.75/2 = 0.875 cm

Dimensions of cuboid

Length= 5.5 cm

Breadth= 10 cm

Height = 3.5 cm

Volume of one silver coin

= pi *(r^2)*h

= 3.141(0.875)(0.875)(0.2)

= 0.481 cm^3

Volume of cuboid

= l * b * h

= 5.5(10)(3.5)

= 192.5 cm^3

No. of coins required to form cuboid

= Volume of cuboid/Volume of one coin

= 192.5/0.481

= 400.207

= 400. (round off)

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