how many six digit even numbers can be formed from digits 1 to 7 such that the digits should not repeat and the second last digit should be even?
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hey dear
here is your answer ☆
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☞ there are 6 places in total
an even number is to be formed which means last place should be occupied only by even numbers, so 3 numbers can fit in that place.
at second last place even number should be placed so 2 numbers can be there ( as one digit is on last place)
now, rest places can be filled in 5! ways
hence, 5! (2) (3) = 720
hope it helps ✌ ✌
here is your answer ☆
===============
☞ there are 6 places in total
an even number is to be formed which means last place should be occupied only by even numbers, so 3 numbers can fit in that place.
at second last place even number should be placed so 2 numbers can be there ( as one digit is on last place)
now, rest places can be filled in 5! ways
hence, 5! (2) (3) = 720
hope it helps ✌ ✌
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