Question

How many slabs of cement are required to tile a platform of length 8 m and breadth 6 m, if the length of each slab is 4 cm and breadth 3 cm ?​

Answer 1

Given:-

• Length of platform = 8 m = 800 cm
• Breadth of platform = 6 m = 600 cm
• Length of slab = 4 cm
• Breadth of slab = 3 cm

To find:-

Number of slabs required to tile the platform.

Solution:-

$\sf{Length\: of\: platform = 800 \:cm}$

$\sf{Breadth\: of\: platform = 600 \:cm}$

$\sf{Area \:of \:rectangle = (Length \times breadth)\:sq.units}$

= $\sf{Area\:of\:Platform = 800 \times 600\:cm^2}$

= $\sf{Area\:of\:Platform = 480000\:cm^2}$

Now,

$\sf{Length\:of\:slab = 4\:cm}$

$\sf{Breadth\:of\:slab = 3\:cm}$

$\sf{Area \:of\:slab= 4\times3\:cm^2}$

=$\sf{Area\:of\:slab = 12\:cm^2}$

$\sf{[To\:find\:the\:Number\:of\:slabs\:we\:need\:to\:divide\:the\:area\:of\:platform\:by\:the\:area\:of\:slabs]}$

Therefore,

$\sf{Number\:of\:slabs = \dfrac{Area\:of\:Platform}{Area\:of\:Slabs}}$

= $\sf{Number\:of\:slabs = \dfrac{480000}{12}}$

= $\sf{Number\:of\:slabs = 40000}$

$\sf{\therefore 40000 \:slabs\:are\:required}$

Additional Information:-

• $\sf{Area\:of\:square = (side)^2\:sq.units}$

• $\sf{Perimeter\:of\:square = (4\times Side) \:units}$

• $\sf{Area\:of\:Rectangle = (Length\times Breadth) \:sq.units}$

• $\sf{Perimeter\:of\:Rectangle = 2(Length + Breadth)\:units.}$

Answer 2

Given

• Length of platform (L) = 8m
• Breadth of platform (B) = 6m
• Length of slab (l) = 4cm
• Breadth of slab (b) = 3cm

To find

• Number of slabs to tile the platform.

Solution

$\underline{\boxed{Area\: of\: a\: rectangle = l × b}}$

★ Area of platform

→ L × B = 8 × 6

→ 48 m² = 480000 cm²

★ Area of a slab

→ l × b = 4 × 3

→ 12 cm²

Now,

$\boxed{Number\: of\: slabs = \frac{Area\: of\: platform}{Area\: of\: a\: slab}}$

Therefore,

$\implies{Number\: of\: slabs = \dfrac{480000}{12}}$

$\implies{Number\: of\: slabs = 40000}$

Hence, 40000 slabs are required to tile the platform.