How many slabs of cement are required to tile a platform of length 8 m and breadth 6 m, if the length of each slab is 4 cm and breadth 3 cm?
Answers
Answered by
9
Answer:
Area of platform to be tiled [ Length=8m,Breadth=6m] = 48m² =480000cm²
Area of cement slab [ Length=4cm ,Breadth =3cm ] = 4×3=12cm²
Number of cement slabs required to tile the platform are 480000/12=40,000
Therefore,40,000 slabs are required .
Step-by-step explanation:
Answered by
3
Area of platform- l×b
=8×6 m^2
= 48 m^2
Area pf each slab- 4×3 m^2
=12 m^2
So, the no. of slabs required = 48/12
=4
Step-by-step explanation:
Hence , the answer is 4 slabs
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