Math, asked by nikhunikhu066, 1 day ago

how many slaps of cement are required to a tile platform of length 6m and breadth 4m ,if the length of each slap is 4cm and breadth 1cm

Answers

Answered by sushenkumar19
1

Answer:

60000 slaps is the answer

Step-by-step explanation:

total area required = 24 m²= 240000cm²

area of one slap= 4 cm²

total no of slaps = 60000

Answered by rumihazarika8
0

60000 slaps

Step-by-step explanation:

length of tile is 6m

breadth of tile is 4m

So the formula of area is l×b

Hence area of tile is 24m²

So 24m² means 24×100 = 2400cm

the length of each slap = 4cm

breadth of each slap = 1cm

Area = l×b

So Area of each slap is 4cm²

number of tiles required = 2400×100/4 = 60000 slaps

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