Question

How many sodium ions are there in 1.06g of sodium carbonate

Answer 1

Answer:

Number of sodium ions present in 1.06g of sodium carbonate is  1.20×10²²

Explanation:

sodium carbonate = Na₂CO₃

Atomic mass of Na = 23 $g/mol$

Atomic mass of Carbon = 12 $g/mol$

Atomic mass of Oxygen = 16 $g/mol$

∴ Molecular mass of sodium carbonate = 106 $g/mol$

Total number of moles in 1.06g sodium carbonate = $\frac{given mass}{molar mass}$

                                                                                    =$\frac{1.06}{106}$

                                                                                     = 0.01 moles

every sodium carbonate molecule has 2 sodium ions,

so, every mole of sodium carbonate will have 2 mole of sodium ions in it

∴0.01 mole of sodium carbonate has= 0.02 moles of sodium ions in it.

∴number of sodium ions present in 1.06g of sodium carbonate

                                                           = 0.02×6.022×10²³

                                                           = 1.20×10²² ions