Question

how many solid coins of 6 cm diameter and 0.2 cm thickness can be made by melting a solid metal cuboid of length 33 cm breadth 18 cm height 8 cm ?

Answer 1

volume of cubiod =lbh
=33×18×8 cm cube
= 4752 cm cube
now cions are made by melting the solid metal cubiod therefore there volume must be equal
Therefore.
volume of circular cions = pie ×r×r×h
= 22/7 ×3×3×0.2 r=d/2 =6/2 =3 and thickness = 0.2
=39.6/7
=396/7×10
no of cions =volume of cubiod/volume of cions
=4752×7×10
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396
=332640
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396
=840 cions
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Answer 2

So first we will find the volume of both coins as well as cuboid.
So first find the volume of cuboid=lbh (l×b×h)
So l = 33 cm, b = 18 cm, h = 8 cm
=33×18×8=4752
Volume of cuboid is 4752 cm.
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Now find the volume of coins=πr2h. (Here height means thickness)
So radius of coin=d/2=6/2=3
So volume of coins=22/7×3×3×0.2
39.6/7=396×7×10
Now we substitude 7 and 10 by multiplying to volume of cuboid, i.e 4752
=4752×7×10
=332640 cm.
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So number of coins made=volume of cuboid÷volume of coins
=332640÷396
= 840
So 840 coins can be made from melting a cuboid of length 33, breadth 18, height 8.
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Hope it help you.
If it help you so if you want you can mark it has brainliest.