How many solution of the linear equation 2x -5y - 7 =0 hove
Answers
A linear equation in two variables can have infinite solutions.
The examples to support the statement are :
1. Let us take the value of x as 0.
So when we write the values of x and y in form of coordinate pairs we get :
2. Let us take value of x as 2.
So when we write the values of x and y in the form of coordinate pairs we get :
Though we take any number as the value of x ; finally we are getting a coordinate pair. These two examples were taken just to prove that an equation can have infinite solutions.
Answer:
A linear equation in two variables can have infinite solutions.
The examples to support the statement are :
1. Let us take the value of x as 0.
\longrightarrow{\tt{2(0) - 5y - 7 = 0}}⟶2(0)−5y−7=0
\longrightarrow{\tt{0 - 5y - 7 =0}}⟶0−5y−7=0
\longrightarrow{\tt{0 - (-7) - 5y = 0}}⟶0−(−7)−5y=0
\longrightarrow{\tt{7 - 5y = 0}}⟶7−5y=0
\longrightarrow{\tt{-5y = -7}}⟶−5y=−7
\longrightarrow{\tt{5y = 7}}⟶5y=7
\longrightarrow{\tt{y = \dfrac{7}{5}}}⟶y=
5
7
So when we write the values of x and y in form of coordinate pairs we get :
\longrightarrow{\tt{(x , y)}}⟶(x,y)
\longrightarrow{\tt{(0 , \dfrac{7}{5})}}⟶(0,
5
7
)
2. Let us take value of x as 2.
\longrightarrow{\tt{2(2) - 5y - 7 = 0}}⟶2(2)−5y−7=0
\longrightarrow{\tt{4 - 5y - 7 = 0}}⟶4−5y−7=0
\longrightarrow{\tt{4 - (-7) - 5y = 0}}⟶4−(−7)−5y=0
\longrightarrow{\tt{11 - 5y = 0}}⟶11−5y=0
\longrightarrow{\tt{-5y = -11}}⟶−5y=−11
\longrightarrow{\tt{5y = 11}}⟶5y=11
\longrightarrow{\tt{y = \dfrac{11}{5}}}⟶y=
5
11
So when we write the values of x and y in the form of coordinate pairs we get :
\longrightarrow{\tt{(x,y)}}⟶(x,y)
\longrightarrow{\tt{(2 , \dfrac{11}{5})}}⟶(2,
5
11
)
Though we take any number as the value of x ; finally we are getting a coordinate pair. These two examples were taken just to prove that an equation can have infinite solutions.