How many solutions does 2+x2=0 have?
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Given equation is actually 2 + x² = 0.
It can also be written as x² + 2 = 0.
=> x² + 2 = 0
=> x² = -2
=> x=±√(-2)
Thus we found out that there are two solutions.
And the two solutions are √(-2) and -√(-2).
These solutions are not real.
By taking √(-1) as ι, we can write the solutions as ι√2 and -ι√2.
Hence, there are two solutions which are ±ι√2.
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